3(6r-5)+2r=(r-5)-5r

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Solution for 3(6r-5)+2r=(r-5)-5r equation: 



3(6r-5)+2r=(r-5)-5r

We move all terms to the left:

3(6r-5)+2r-((r-5)-5r)=0

We add all the numbers together, and all the variables

2r+3(6r-5)-((r-5)-5r)=0

We multiply parentheses

2r+18r-((r-5)-5r)-15=0



We calculate terms in parentheses: -((r-5)-5r), so:

(r-5)-5r

We add all the numbers together, and all the variables

-5r+(r-5)

We get rid of parentheses

-5r+r-5

We add all the numbers together, and all the variables

-4r-5

Back to the equation:

-(-4r-5)



We add all the numbers together, and all the variables

20r-(-4r-5)-15=0

We get rid of parentheses

20r+4r+5-15=0

We add all the numbers together, and all the variables

24r-10=0

We move all terms containing r to the left, all other terms to the right

24r=10

r=10/24

r=5/12

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