3(6x+1)=4(x-5)-2

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Solution for 3(6x+1)=4(x-5)-2 equation: 



3(6x+1)=4(x-5)-2

We move all terms to the left:

3(6x+1)-(4(x-5)-2)=0

We multiply parentheses

18x-(4(x-5)-2)+3=0



We calculate terms in parentheses: -(4(x-5)-2), so:

4(x-5)-2

We multiply parentheses

4x-20-2

We add all the numbers together, and all the variables

4x-22

Back to the equation:

-(4x-22)



We get rid of parentheses

18x-4x+22+3=0

We add all the numbers together, and all the variables

14x+25=0

We move all terms containing x to the left, all other terms to the right

14x=-25

x=-25/14

x=-1+11/14

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