3(6x+12)+4x=20

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Solution for 3(6x+12)+4x=20 equation: 



3(6x+12)+4x=20

We move all terms to the left:

3(6x+12)+4x-(20)=0

We add all the numbers together, and all the variables

4x+3(6x+12)-20=0

We multiply parentheses

4x+18x+36-20=0

We add all the numbers together, and all the variables

22x+16=0

We move all terms containing x to the left, all other terms to the right

22x=-16

x=-16/22

x=-8/11

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