3(6x+3)-5(3x-4)=5+2(x+3)

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Solution for 3(6x+3)-5(3x-4)=5+2(x+3) equation: 



3(6x+3)-5(3x-4)=5+2(x+3)

We move all terms to the left:

3(6x+3)-5(3x-4)-(5+2(x+3))=0

We multiply parentheses

18x-15x-(5+2(x+3))+9+20=0



We calculate terms in parentheses: -(5+2(x+3)), so:

5+2(x+3)

determiningTheFunctionDomain
2(x+3)+5

We multiply parentheses

2x+6+5

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We add all the numbers together, and all the variables

3x-(2x+11)+29=0

We get rid of parentheses

3x-2x-11+29=0

We add all the numbers together, and all the variables

x+18=0

We move all terms containing x to the left, all other terms to the right

x=-18

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