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3(6x+3)x=8
We move all terms to the left:
3(6x+3)x-(8)=0
We multiply parentheses
18x^2+9x-8=0
a = 18; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·18·(-8)
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{73}}{2*18}=\frac{-9-3\sqrt{73}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{73}}{2*18}=\frac{-9+3\sqrt{73}}{36} $
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