3(6x-3)-4(2x-5)=3(3x+4)-11

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Solution for 3(6x-3)-4(2x-5)=3(3x+4)-11 equation: 



3(6x-3)-4(2x-5)=3(3x+4)-11

We move all terms to the left:

3(6x-3)-4(2x-5)-(3(3x+4)-11)=0

We multiply parentheses

18x-8x-(3(3x+4)-11)-9+20=0



We calculate terms in parentheses: -(3(3x+4)-11), so:

3(3x+4)-11

We multiply parentheses

9x+12-11

We add all the numbers together, and all the variables

9x+1

Back to the equation:

-(9x+1)



We add all the numbers together, and all the variables

10x-(9x+1)+11=0

We get rid of parentheses

10x-9x-1+11=0

We add all the numbers together, and all the variables

x+10=0

We move all terms containing x to the left, all other terms to the right

x=-10

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