3(6x-4(1+2x))+20=32

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Solution for 3(6x-4(1+2x))+20=32 equation:


Simplifying
3(6x + -4(1 + 2x)) + 20 = 32
3(6x + (1 * -4 + 2x * -4)) + 20 = 32
3(6x + (-4 + -8x)) + 20 = 32

Reorder the terms:
3(-4 + 6x + -8x) + 20 = 32

Combine like terms: 6x + -8x = -2x
3(-4 + -2x) + 20 = 32
(-4 * 3 + -2x * 3) + 20 = 32
(-12 + -6x) + 20 = 32

Reorder the terms:
-12 + 20 + -6x = 32

Combine like terms: -12 + 20 = 8
8 + -6x = 32

Solving
8 + -6x = 32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -6x = 32 + -8

Combine like terms: 8 + -8 = 0
0 + -6x = 32 + -8
-6x = 32 + -8

Combine like terms: 32 + -8 = 24
-6x = 24

Divide each side by '-6'.
x = -4

Simplifying
x = -4

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