3(6x-4)+7x=4x-12+21x

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Solution for 3(6x-4)+7x=4x-12+21x equation: 



3(6x-4)+7x=4x-12+21x

We move all terms to the left:

3(6x-4)+7x-(4x-12+21x)=0

We add all the numbers together, and all the variables

3(6x-4)+7x-(25x-12)=0

We add all the numbers together, and all the variables

7x+3(6x-4)-(25x-12)=0

We multiply parentheses

7x+18x-(25x-12)-12=0

We get rid of parentheses

7x+18x-25x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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