3(6x-4)=-10+8(2x+1)

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Solution for 3(6x-4)=-10+8(2x+1) equation: 



3(6x-4)=-10+8(2x+1)

We move all terms to the left:

3(6x-4)-(-10+8(2x+1))=0

We multiply parentheses

18x-(-10+8(2x+1))-12=0



We calculate terms in parentheses: -(-10+8(2x+1)), so:

-10+8(2x+1)

determiningTheFunctionDomain
8(2x+1)-10

We multiply parentheses

16x+8-10

We add all the numbers together, and all the variables

16x-2

Back to the equation:

-(16x-2)



We get rid of parentheses

18x-16x+2-12=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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