3(6x-5)+2(x+4)=4(x+3)-(x+9)

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Solution for 3(6x-5)+2(x+4)=4(x+3)-(x+9) equation: 



3(6x-5)+2(x+4)=4(x+3)-(x+9)

We move all terms to the left:

3(6x-5)+2(x+4)-(4(x+3)-(x+9))=0

We multiply parentheses

18x+2x-(4(x+3)-(x+9))-15+8=0



We calculate terms in parentheses: -(4(x+3)-(x+9)), so:

4(x+3)-(x+9)

We multiply parentheses

4x-(x+9)+12

We get rid of parentheses

4x-x-9+12

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

20x-(3x+3)-7=0

We get rid of parentheses

20x-3x-3-7=0

We add all the numbers together, and all the variables

17x-10=0

We move all terms containing x to the left, all other terms to the right

17x=10

x=10/17

x=10/17

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