3(6x-5)-3(3x-18)=2(4x+2)-3

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Solution for 3(6x-5)-3(3x-18)=2(4x+2)-3 equation: 



3(6x-5)-3(3x-18)=2(4x+2)-3

We move all terms to the left:

3(6x-5)-3(3x-18)-(2(4x+2)-3)=0

We multiply parentheses

18x-9x-(2(4x+2)-3)-15+54=0



We calculate terms in parentheses: -(2(4x+2)-3), so:

2(4x+2)-3

We multiply parentheses

8x+4-3

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We add all the numbers together, and all the variables

9x-(8x+1)+39=0

We get rid of parentheses

9x-8x-1+39=0

We add all the numbers together, and all the variables

x+38=0

We move all terms containing x to the left, all other terms to the right

x=-38

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