3(6y+1)=4(5y+4)

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Solution for 3(6y+1)=4(5y+4) equation: 



3(6y+1)=4(5y+4)

We move all terms to the left:

3(6y+1)-(4(5y+4))=0

We multiply parentheses

18y-(4(5y+4))+3=0



We calculate terms in parentheses: -(4(5y+4)), so:

4(5y+4)

We multiply parentheses

20y+16

Back to the equation:

-(20y+16)



We get rid of parentheses

18y-20y-16+3=0

We add all the numbers together, and all the variables

-2y-13=0

We move all terms containing y to the left, all other terms to the right

-2y=13

y=13/-2

y=-6+1/2

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