3(6y-3)+15=4(2y+4)+22

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Solution for 3(6y-3)+15=4(2y+4)+22 equation: 



3(6y-3)+15=4(2y+4)+22

We move all terms to the left:

3(6y-3)+15-(4(2y+4)+22)=0

We multiply parentheses

18y-(4(2y+4)+22)-9+15=0



We calculate terms in parentheses: -(4(2y+4)+22), so:

4(2y+4)+22

We multiply parentheses

8y+16+22

We add all the numbers together, and all the variables

8y+38

Back to the equation:

-(8y+38)



We add all the numbers together, and all the variables

18y-(8y+38)+6=0

We get rid of parentheses

18y-8y-38+6=0

We add all the numbers together, and all the variables

10y-32=0

We move all terms containing y to the left, all other terms to the right

10y=32

y=32/10

y=3+1/5

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