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3(6y-3)-1=10y-2(y+10)
We move all terms to the left:
3(6y-3)-1-(10y-2(y+10))=0
We multiply parentheses
18y-(10y-2(y+10))-9-1=0
We calculate terms in parentheses: -(10y-2(y+10)), so:We add all the numbers together, and all the variables
10y-2(y+10)
We multiply parentheses
10y-2y-20
We add all the numbers together, and all the variables
8y-20
Back to the equation:
-(8y-20)
18y-(8y-20)-10=0
We get rid of parentheses
18y-8y+20-10=0
We add all the numbers together, and all the variables
10y+10=0
We move all terms containing y to the left, all other terms to the right
10y=-10
y=-10/10
y=-1
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