3(6y-3)-1=10y-2(y+10)

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Solution for 3(6y-3)-1=10y-2(y+10) equation: 



3(6y-3)-1=10y-2(y+10)

We move all terms to the left:

3(6y-3)-1-(10y-2(y+10))=0

We multiply parentheses

18y-(10y-2(y+10))-9-1=0



We calculate terms in parentheses: -(10y-2(y+10)), so:

10y-2(y+10)

We multiply parentheses

10y-2y-20

We add all the numbers together, and all the variables

8y-20

Back to the equation:

-(8y-20)



We add all the numbers together, and all the variables

18y-(8y-20)-10=0

We get rid of parentheses

18y-8y+20-10=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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