3(6z-1)-2(z+1)=12(z+1)

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Solution for 3(6z-1)-2(z+1)=12(z+1) equation:


Simplifying
3(6z + -1) + -2(z + 1) = 12(z + 1)

Reorder the terms:
3(-1 + 6z) + -2(z + 1) = 12(z + 1)
(-1 * 3 + 6z * 3) + -2(z + 1) = 12(z + 1)
(-3 + 18z) + -2(z + 1) = 12(z + 1)

Reorder the terms:
-3 + 18z + -2(1 + z) = 12(z + 1)
-3 + 18z + (1 * -2 + z * -2) = 12(z + 1)
-3 + 18z + (-2 + -2z) = 12(z + 1)

Reorder the terms:
-3 + -2 + 18z + -2z = 12(z + 1)

Combine like terms: -3 + -2 = -5
-5 + 18z + -2z = 12(z + 1)

Combine like terms: 18z + -2z = 16z
-5 + 16z = 12(z + 1)

Reorder the terms:
-5 + 16z = 12(1 + z)
-5 + 16z = (1 * 12 + z * 12)
-5 + 16z = (12 + 12z)

Solving
-5 + 16z = 12 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
-5 + 16z + -12z = 12 + 12z + -12z

Combine like terms: 16z + -12z = 4z
-5 + 4z = 12 + 12z + -12z

Combine like terms: 12z + -12z = 0
-5 + 4z = 12 + 0
-5 + 4z = 12

Add '5' to each side of the equation.
-5 + 5 + 4z = 12 + 5

Combine like terms: -5 + 5 = 0
0 + 4z = 12 + 5
4z = 12 + 5

Combine like terms: 12 + 5 = 17
4z = 17

Divide each side by '4'.
z = 4.25

Simplifying
z = 4.25

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