3(6z-1)-2(z+1)=14(z+1)

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Solution for 3(6z-1)-2(z+1)=14(z+1) equation:


Simplifying
3(6z + -1) + -2(z + 1) = 14(z + 1)

Reorder the terms:
3(-1 + 6z) + -2(z + 1) = 14(z + 1)
(-1 * 3 + 6z * 3) + -2(z + 1) = 14(z + 1)
(-3 + 18z) + -2(z + 1) = 14(z + 1)

Reorder the terms:
-3 + 18z + -2(1 + z) = 14(z + 1)
-3 + 18z + (1 * -2 + z * -2) = 14(z + 1)
-3 + 18z + (-2 + -2z) = 14(z + 1)

Reorder the terms:
-3 + -2 + 18z + -2z = 14(z + 1)

Combine like terms: -3 + -2 = -5
-5 + 18z + -2z = 14(z + 1)

Combine like terms: 18z + -2z = 16z
-5 + 16z = 14(z + 1)

Reorder the terms:
-5 + 16z = 14(1 + z)
-5 + 16z = (1 * 14 + z * 14)
-5 + 16z = (14 + 14z)

Solving
-5 + 16z = 14 + 14z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-14z' to each side of the equation.
-5 + 16z + -14z = 14 + 14z + -14z

Combine like terms: 16z + -14z = 2z
-5 + 2z = 14 + 14z + -14z

Combine like terms: 14z + -14z = 0
-5 + 2z = 14 + 0
-5 + 2z = 14

Add '5' to each side of the equation.
-5 + 5 + 2z = 14 + 5

Combine like terms: -5 + 5 = 0
0 + 2z = 14 + 5
2z = 14 + 5

Combine like terms: 14 + 5 = 19
2z = 19

Divide each side by '2'.
z = 9.5

Simplifying
z = 9.5

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