3(6z-1)-2(z+3)=14(z+1)

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Solution for 3(6z-1)-2(z+3)=14(z+1) equation: 



3(6z-1)-2(z+3)=14(z+1)

We move all terms to the left:

3(6z-1)-2(z+3)-(14(z+1))=0

We multiply parentheses

18z-2z-(14(z+1))-3-6=0



We calculate terms in parentheses: -(14(z+1)), so:

14(z+1)

We multiply parentheses

14z+14

Back to the equation:

-(14z+14)



We add all the numbers together, and all the variables

16z-(14z+14)-9=0

We get rid of parentheses

16z-14z-14-9=0

We add all the numbers together, and all the variables

2z-23=0

We move all terms containing z to the left, all other terms to the right

2z=23

z=23/2

z=11+1/2

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