3(6z-1)-3(2+2)=4(2+1)

Solution for 3(6z-1)-3(2+2)=4(2+1) equation:

Simplifying
3(6z + -1) + -3(2 + 2) = 4(2 + 1)

Reorder the terms:
3(-1 + 6z) + -3(2 + 2) = 4(2 + 1)
(-1 * 3 + 6z * 3) + -3(2 + 2) = 4(2 + 1)
(-3 + 18z) + -3(2 + 2) = 4(2 + 1)

Combine like terms: 2 + 2 = 4
-3 + 18z + -3(4) = 4(2 + 1)

Multiply -3 * 4
-3 + 18z + -12 = 4(2 + 1)

Reorder the terms:
-3 + -12 + 18z = 4(2 + 1)

Combine like terms: -3 + -12 = -15
-15 + 18z = 4(2 + 1)

Combine like terms: 2 + 1 = 3
-15 + 18z = 4(3)

Multiply 4 * 3
-15 + 18z = 12

Solving
-15 + 18z = 12

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 18z = 12 + 15

Combine like terms: -15 + 15 = 0
0 + 18z = 12 + 15
18z = 12 + 15

Combine like terms: 12 + 15 = 27
18z = 27

Divide each side by '18'.
z = 1.5

Simplifying
z = 1.5