3(6z-1)-4(z+4)=10(2+1)

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Solution for 3(6z-1)-4(z+4)=10(2+1) equation:


Simplifying
3(6z + -1) + -4(z + 4) = 10(2 + 1)

Reorder the terms:
3(-1 + 6z) + -4(z + 4) = 10(2 + 1)
(-1 * 3 + 6z * 3) + -4(z + 4) = 10(2 + 1)
(-3 + 18z) + -4(z + 4) = 10(2 + 1)

Reorder the terms:
-3 + 18z + -4(4 + z) = 10(2 + 1)
-3 + 18z + (4 * -4 + z * -4) = 10(2 + 1)
-3 + 18z + (-16 + -4z) = 10(2 + 1)

Reorder the terms:
-3 + -16 + 18z + -4z = 10(2 + 1)

Combine like terms: -3 + -16 = -19
-19 + 18z + -4z = 10(2 + 1)

Combine like terms: 18z + -4z = 14z
-19 + 14z = 10(2 + 1)

Combine like terms: 2 + 1 = 3
-19 + 14z = 10(3)

Multiply 10 * 3
-19 + 14z = 30

Solving
-19 + 14z = 30

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '19' to each side of the equation.
-19 + 19 + 14z = 30 + 19

Combine like terms: -19 + 19 = 0
0 + 14z = 30 + 19
14z = 30 + 19

Combine like terms: 30 + 19 = 49
14z = 49

Divide each side by '14'.
z = 3.5

Simplifying
z = 3.5

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