3(6z-1)-4(z+8)=2(z+1)

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Solution for 3(6z-1)-4(z+8)=2(z+1) equation:


Simplifying
3(6z + -1) + -4(z + 8) = 2(z + 1)

Reorder the terms:
3(-1 + 6z) + -4(z + 8) = 2(z + 1)
(-1 * 3 + 6z * 3) + -4(z + 8) = 2(z + 1)
(-3 + 18z) + -4(z + 8) = 2(z + 1)

Reorder the terms:
-3 + 18z + -4(8 + z) = 2(z + 1)
-3 + 18z + (8 * -4 + z * -4) = 2(z + 1)
-3 + 18z + (-32 + -4z) = 2(z + 1)

Reorder the terms:
-3 + -32 + 18z + -4z = 2(z + 1)

Combine like terms: -3 + -32 = -35
-35 + 18z + -4z = 2(z + 1)

Combine like terms: 18z + -4z = 14z
-35 + 14z = 2(z + 1)

Reorder the terms:
-35 + 14z = 2(1 + z)
-35 + 14z = (1 * 2 + z * 2)
-35 + 14z = (2 + 2z)

Solving
-35 + 14z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-35 + 14z + -2z = 2 + 2z + -2z

Combine like terms: 14z + -2z = 12z
-35 + 12z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-35 + 12z = 2 + 0
-35 + 12z = 2

Add '35' to each side of the equation.
-35 + 35 + 12z = 2 + 35

Combine like terms: -35 + 35 = 0
0 + 12z = 2 + 35
12z = 2 + 35

Combine like terms: 2 + 35 = 37
12z = 37

Divide each side by '12'.
z = 3.083333333

Simplifying
z = 3.083333333

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