3(6z-1)-5(z+2)=2(z+1)

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Solution for 3(6z-1)-5(z+2)=2(z+1) equation:


Simplifying
3(6z + -1) + -5(z + 2) = 2(z + 1)

Reorder the terms:
3(-1 + 6z) + -5(z + 2) = 2(z + 1)
(-1 * 3 + 6z * 3) + -5(z + 2) = 2(z + 1)
(-3 + 18z) + -5(z + 2) = 2(z + 1)

Reorder the terms:
-3 + 18z + -5(2 + z) = 2(z + 1)
-3 + 18z + (2 * -5 + z * -5) = 2(z + 1)
-3 + 18z + (-10 + -5z) = 2(z + 1)

Reorder the terms:
-3 + -10 + 18z + -5z = 2(z + 1)

Combine like terms: -3 + -10 = -13
-13 + 18z + -5z = 2(z + 1)

Combine like terms: 18z + -5z = 13z
-13 + 13z = 2(z + 1)

Reorder the terms:
-13 + 13z = 2(1 + z)
-13 + 13z = (1 * 2 + z * 2)
-13 + 13z = (2 + 2z)

Solving
-13 + 13z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-13 + 13z + -2z = 2 + 2z + -2z

Combine like terms: 13z + -2z = 11z
-13 + 11z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-13 + 11z = 2 + 0
-13 + 11z = 2

Add '13' to each side of the equation.
-13 + 13 + 11z = 2 + 13

Combine like terms: -13 + 13 = 0
0 + 11z = 2 + 13
11z = 2 + 13

Combine like terms: 2 + 13 = 15
11z = 15

Divide each side by '11'.
z = 1.363636364

Simplifying
z = 1.363636364

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