3(6z-15)=2(6z-4)

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Solution for 3(6z-15)=2(6z-4) equation: 



3(6z-15)=2(6z-4)

We move all terms to the left:

3(6z-15)-(2(6z-4))=0

We multiply parentheses

18z-(2(6z-4))-45=0



We calculate terms in parentheses: -(2(6z-4)), so:

2(6z-4)

We multiply parentheses

12z-8

Back to the equation:

-(12z-8)



We get rid of parentheses

18z-12z+8-45=0

We add all the numbers together, and all the variables

6z-37=0

We move all terms containing z to the left, all other terms to the right

6z=37

z=37/6

z=6+1/6

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