3(7+2)+4=5(y-1)+y

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Solution for 3(7+2)+4=5(y-1)+y equation: 



3(7+2)+4=5(y-1)+y

We move all terms to the left:

3(7+2)+4-(5(y-1)+y)=0

We add all the numbers together, and all the variables

-(5(y-1)+y)+4+39=0

We add all the numbers together, and all the variables

-(5(y-1)+y)+43=0



We calculate terms in parentheses: -(5(y-1)+y), so:

5(y-1)+y

We add all the numbers together, and all the variables

y+5(y-1)

We multiply parentheses

y+5y-5

We add all the numbers together, and all the variables

6y-5

Back to the equation:

-(6y-5)



We get rid of parentheses

-6y+5+43=0

We add all the numbers together, and all the variables

-6y+48=0

We move all terms containing y to the left, all other terms to the right

-6y=-48

y=-48/-6

y=+8

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