3(7+2a)+5(1+a)=-7a+5a

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Solution for 3(7+2a)+5(1+a)=-7a+5a equation: 



3(7+2a)+5(1+a)=-7a+5a

We move all terms to the left:

3(7+2a)+5(1+a)-(-7a+5a)=0

We add all the numbers together, and all the variables

3(2a+7)+5(a+1)-(-2a)=0

We multiply parentheses

6a+5a-(-2a)+21+5=0

We get rid of parentheses

6a+5a+2a+21+5=0

We add all the numbers together, and all the variables

13a+26=0

We move all terms containing a to the left, all other terms to the right

13a=-26

a=-26/13

a=-2

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