3(7+2k)=30+3(k-1)

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Solution for 3(7+2k)=30+3(k-1) equation: 



3(7+2k)=30+3(k-1)

We move all terms to the left:

3(7+2k)-(30+3(k-1))=0

We add all the numbers together, and all the variables

3(2k+7)-(30+3(k-1))=0

We multiply parentheses

6k-(30+3(k-1))+21=0



We calculate terms in parentheses: -(30+3(k-1)), so:

30+3(k-1)

determiningTheFunctionDomain
3(k-1)+30

We multiply parentheses

3k-3+30

We add all the numbers together, and all the variables

3k+27

Back to the equation:

-(3k+27)



We get rid of parentheses

6k-3k-27+21=0

We add all the numbers together, and all the variables

3k-6=0

We move all terms containing k to the left, all other terms to the right

3k=6

k=6/3

k=2

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