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3(7+2x)+3=3(5+x)-9(x+1)
We move all terms to the left:
3(7+2x)+3-(3(5+x)-9(x+1))=0
We add all the numbers together, and all the variables
3(2x+7)-(3(x+5)-9(x+1))+3=0
We multiply parentheses
6x-(3(x+5)-9(x+1))+21+3=0
We calculate terms in parentheses: -(3(x+5)-9(x+1)), so:We add all the numbers together, and all the variables
3(x+5)-9(x+1)
We multiply parentheses
3x-9x+15-9
We add all the numbers together, and all the variables
-6x+6
Back to the equation:
-(-6x+6)
6x-(-6x+6)+24=0
We get rid of parentheses
6x+6x-6+24=0
We add all the numbers together, and all the variables
12x+18=0
We move all terms containing x to the left, all other terms to the right
12x=-18
x=-18/12
x=-1+1/2
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