3(7+2x)+6x=9-3(x-4)

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Solution for 3(7+2x)+6x=9-3(x-4) equation: 



3(7+2x)+6x=9-3(x-4)

We move all terms to the left:

3(7+2x)+6x-(9-3(x-4))=0

We add all the numbers together, and all the variables

3(2x+7)+6x-(9-3(x-4))=0

We add all the numbers together, and all the variables

6x+3(2x+7)-(9-3(x-4))=0

We multiply parentheses

6x+6x-(9-3(x-4))+21=0



We calculate terms in parentheses: -(9-3(x-4)), so:

9-3(x-4)

determiningTheFunctionDomain
-3(x-4)+9

We multiply parentheses

-3x+12+9

We add all the numbers together, and all the variables

-3x+21

Back to the equation:

-(-3x+21)



We add all the numbers together, and all the variables

12x-(-3x+21)+21=0

We get rid of parentheses

12x+3x-21+21=0

We add all the numbers together, and all the variables

15x=0

x=0/15

x=0

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