3(7+4b)=21+b

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Solution for 3(7+4b)=21+b equation: 



3(7+4b)=21+b

We move all terms to the left:

3(7+4b)-(21+b)=0

We add all the numbers together, and all the variables

3(4b+7)-(b+21)=0

We multiply parentheses

12b-(b+21)+21=0

We get rid of parentheses

12b-b-21+21=0

We add all the numbers together, and all the variables

11b=0

b=0/11

b=0

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