3(7+9k)+23k=4K-(24-k)

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Solution for 3(7+9k)+23k=4K-(24-k) equation: 



3(7+9k)+23k=4-(24-k)

We move all terms to the left:

3(7+9k)+23k-(4-(24-k))=0

We add all the numbers together, and all the variables

3(9k+7)+23k-(4-(-1k+24))=0

We add all the numbers together, and all the variables

23k+3(9k+7)-(4-(-1k+24))=0

We multiply parentheses

23k+27k-(4-(-1k+24))+21=0



We calculate terms in parentheses: -(4-(-1k+24)), so:

4-(-1k+24)

determiningTheFunctionDomain
-(-1k+24)+4

We get rid of parentheses

1k-24+4

We add all the numbers together, and all the variables

k-20

Back to the equation:

-(k-20)



We add all the numbers together, and all the variables

50k-(k-20)+21=0

We get rid of parentheses

50k-k+20+21=0

We add all the numbers together, and all the variables

49k+41=0

We move all terms containing k to the left, all other terms to the right

49k=-41

k=-41/49

k=-41/49

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