3(7-2(7x-4))=-42x+45

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Solution for 3(7-2(7x-4))=-42x+45 equation: 



3(7-2(7x-4))=-42x+45

We move all terms to the left:

3(7-2(7x-4))-(-42x+45)=0

We get rid of parentheses

3(7-2(7x-4))+42x-45=0

We add all the numbers together, and all the variables

42x+3(7-2(7x-4))-45=0

We move all terms containing x to the left, all other terms to the right

42x+3(7-2(7x-4))=45

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