3(7-2a)=(126-5a)

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Solution for 3(7-2a)=(126-5a) equation: 



3(7-2a)=(126-5a)

We move all terms to the left:

3(7-2a)-((126-5a))=0

We add all the numbers together, and all the variables

3(-2a+7)-((-5a+126))=0

We multiply parentheses

-6a-((-5a+126))+21=0



We calculate terms in parentheses: -((-5a+126)), so:

(-5a+126)

We get rid of parentheses

-5a+126

Back to the equation:

-(-5a+126)



We get rid of parentheses

-6a+5a-126+21=0

We add all the numbers together, and all the variables

-1a-105=0

We move all terms containing a to the left, all other terms to the right

-a=105

a=105/-1

a=-105

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