3(7-4(5a-3))=6(8-8a)+45

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Solution for 3(7-4(5a-3))=6(8-8a)+45 equation: 



3(7-4(5a-3))=6(8-8a)+45

We move all terms to the left:

3(7-4(5a-3))-(6(8-8a)+45)=0

We add all the numbers together, and all the variables

3(7-4(5a-3))-(6(-8a+8)+45)=0



We calculate terms in parentheses: -(6(-8a+8)+45), so:

6(-8a+8)+45

We multiply parentheses

-48a+48+45

We add all the numbers together, and all the variables

-48a+93

Back to the equation:

-(-48a+93)



We get rid of parentheses

3(7-4(5a-3))+48a-93=0

We add all the numbers together, and all the variables

48a+3(7-4(5a-3))-93=0

We move all terms containing a to the left, all other terms to the right

48a+3(7-4(5a-3))=93

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