3(7-6+3x)+8x=-6+3(12x-24-18x)

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Solution for 3(7-6+3x)+8x=-6+3(12x-24-18x) equation: 



3(7-6+3x)+8x=-6+3(12x-24-18x)

We move all terms to the left:

3(7-6+3x)+8x-(-6+3(12x-24-18x))=0

We add all the numbers together, and all the variables

3(3x+1)+8x-(-6+3(-6x-24))=0

We add all the numbers together, and all the variables

8x+3(3x+1)-(-6+3(-6x-24))=0

We multiply parentheses

8x+9x-(-6+3(-6x-24))+3=0



We calculate terms in parentheses: -(-6+3(-6x-24)), so:

-6+3(-6x-24)

determiningTheFunctionDomain
3(-6x-24)-6

We multiply parentheses

-18x-72-6

We add all the numbers together, and all the variables

-18x-78

Back to the equation:

-(-18x-78)



We add all the numbers together, and all the variables

17x-(-18x-78)+3=0

We get rid of parentheses

17x+18x+78+3=0

We add all the numbers together, and all the variables

35x+81=0

We move all terms containing x to the left, all other terms to the right

35x=-81

x=-81/35

x=-2+11/35

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