3(7-9k)+23k=4k-(24-k)

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Solution for 3(7-9k)+23k=4k-(24-k) equation:



3(7-9k)+23k=4k-(24-k)
We move all terms to the left:
3(7-9k)+23k-(4k-(24-k))=0
We add all the numbers together, and all the variables
3(-9k+7)+23k-(4k-(-1k+24))=0
We add all the numbers together, and all the variables
23k+3(-9k+7)-(4k-(-1k+24))=0
We multiply parentheses
23k-27k-(4k-(-1k+24))+21=0
We calculate terms in parentheses: -(4k-(-1k+24)), so:
4k-(-1k+24)
We get rid of parentheses
4k+1k-24
We add all the numbers together, and all the variables
5k-24
Back to the equation:
-(5k-24)
We add all the numbers together, and all the variables
-4k-(5k-24)+21=0
We get rid of parentheses
-4k-5k+24+21=0
We add all the numbers together, and all the variables
-9k+45=0
We move all terms containing k to the left, all other terms to the right
-9k=-45
k=-45/-9
k=+5

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