3(7-9x)+23x=4x-(24-x)

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Solution for 3(7-9x)+23x=4x-(24-x) equation: 



3(7-9x)+23x=4x-(24-x)

We move all terms to the left:

3(7-9x)+23x-(4x-(24-x))=0

We add all the numbers together, and all the variables

3(-9x+7)+23x-(4x-(-1x+24))=0

We add all the numbers together, and all the variables

23x+3(-9x+7)-(4x-(-1x+24))=0

We multiply parentheses

23x-27x-(4x-(-1x+24))+21=0



We calculate terms in parentheses: -(4x-(-1x+24)), so:

4x-(-1x+24)

We get rid of parentheses

4x+1x-24

We add all the numbers together, and all the variables

5x-24

Back to the equation:

-(5x-24)



We add all the numbers together, and all the variables

-4x-(5x-24)+21=0

We get rid of parentheses

-4x-5x+24+21=0

We add all the numbers together, and all the variables

-9x+45=0

We move all terms containing x to the left, all other terms to the right

-9x=-45

x=-45/-9

x=+5

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