3(7-c)=6(c-4)

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Solution for 3(7-c)=6(c-4) equation: 



3(7-c)=6(c-4)

We move all terms to the left:

3(7-c)-(6(c-4))=0

We add all the numbers together, and all the variables

3(-1c+7)-(6(c-4))=0

We multiply parentheses

-3c-(6(c-4))+21=0



We calculate terms in parentheses: -(6(c-4)), so:

6(c-4)

We multiply parentheses

6c-24

Back to the equation:

-(6c-24)



We get rid of parentheses

-3c-6c+24+21=0

We add all the numbers together, and all the variables

-9c+45=0

We move all terms containing c to the left, all other terms to the right

-9c=-45

c=-45/-9

c=+5

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