3(7-z)-33=21z-4(3+6z)

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Solution for 3(7-z)-33=21z-4(3+6z) equation: 



3(7-z)-33=21z-4(3+6z)

We move all terms to the left:

3(7-z)-33-(21z-4(3+6z))=0

We add all the numbers together, and all the variables

3(-1z+7)-(21z-4(6z+3))-33=0

We multiply parentheses

-3z-(21z-4(6z+3))+21-33=0



We calculate terms in parentheses: -(21z-4(6z+3)), so:

21z-4(6z+3)

We multiply parentheses

21z-24z-12

We add all the numbers together, and all the variables

-3z-12

Back to the equation:

-(-3z-12)



We add all the numbers together, and all the variables

-3z-(-3z-12)-12=0

We get rid of parentheses

-3z+3z+12-12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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