3(7a+3)-5a+55=12(a+7)

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Solution for 3(7a+3)-5a+55=12(a+7) equation: 



3(7a+3)-5a+55=12(a+7)

We move all terms to the left:

3(7a+3)-5a+55-(12(a+7))=0

We add all the numbers together, and all the variables

-5a+3(7a+3)-(12(a+7))+55=0

We multiply parentheses

-5a+21a-(12(a+7))+9+55=0



We calculate terms in parentheses: -(12(a+7)), so:

12(a+7)

We multiply parentheses

12a+84

Back to the equation:

-(12a+84)



We add all the numbers together, and all the variables

16a-(12a+84)+64=0

We get rid of parentheses

16a-12a-84+64=0

We add all the numbers together, and all the variables

4a-20=0

We move all terms containing a to the left, all other terms to the right

4a=20

a=20/4

a=5

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