3(7a+3)=4(a+12)

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Solution for 3(7a+3)=4(a+12) equation: 



3(7a+3)=4(a+12)

We move all terms to the left:

3(7a+3)-(4(a+12))=0

We multiply parentheses

21a-(4(a+12))+9=0



We calculate terms in parentheses: -(4(a+12)), so:

4(a+12)

We multiply parentheses

4a+48

Back to the equation:

-(4a+48)



We get rid of parentheses

21a-4a-48+9=0

We add all the numbers together, and all the variables

17a-39=0

We move all terms containing a to the left, all other terms to the right

17a=39

a=39/17

a=2+5/17

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