3(7a-5)-7=38+6a

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Solution for 3(7a-5)-7=38+6a equation:



3(7a-5)-7=38+6a
We move all terms to the left:
3(7a-5)-7-(38+6a)=0
We add all the numbers together, and all the variables
3(7a-5)-(6a+38)-7=0
We multiply parentheses
21a-(6a+38)-15-7=0
We get rid of parentheses
21a-6a-38-15-7=0
We add all the numbers together, and all the variables
15a-60=0
We move all terms containing a to the left, all other terms to the right
15a=60
a=60/15
a=4

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