3(7a-5)=4(a-8)

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Solution for 3(7a-5)=4(a-8) equation: 



3(7a-5)=4(a-8)

We move all terms to the left:

3(7a-5)-(4(a-8))=0

We multiply parentheses

21a-(4(a-8))-15=0



We calculate terms in parentheses: -(4(a-8)), so:

4(a-8)

We multiply parentheses

4a-32

Back to the equation:

-(4a-32)



We get rid of parentheses

21a-4a+32-15=0

We add all the numbers together, and all the variables

17a+17=0

We move all terms containing a to the left, all other terms to the right

17a=-17

a=-17/17

a=-1

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