3(7b-6)-18=12

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Solution for 3(7b-6)-18=12 equation: 



3(7b-6)-18=12

We move all terms to the left:

3(7b-6)-18-(12)=0

We add all the numbers together, and all the variables

3(7b-6)-30=0

We multiply parentheses

21b-18-30=0

We add all the numbers together, and all the variables

21b-48=0

We move all terms containing b to the left, all other terms to the right

21b=48

b=48/21

b=2+2/7

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