3(7b-6)=-32+7b

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Solution for 3(7b-6)=-32+7b equation: 



3(7b-6)=-32+7b

We move all terms to the left:

3(7b-6)-(-32+7b)=0

We add all the numbers together, and all the variables

3(7b-6)-(7b-32)=0

We multiply parentheses

21b-(7b-32)-18=0

We get rid of parentheses

21b-7b+32-18=0

We add all the numbers together, and all the variables

14b+14=0

We move all terms containing b to the left, all other terms to the right

14b=-14

b=-14/14

b=-1

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