3(7c+1)-26=18c+4

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Solution for 3(7c+1)-26=18c+4 equation: 



3(7c+1)-26=18c+4

We move all terms to the left:

3(7c+1)-26-(18c+4)=0

We multiply parentheses

21c-(18c+4)+3-26=0

We get rid of parentheses

21c-18c-4+3-26=0

We add all the numbers together, and all the variables

3c-27=0

We move all terms containing c to the left, all other terms to the right

3c=27

c=27/3

c=9

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