3(7c+1)-31=15c+2

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Solution for 3(7c+1)-31=15c+2 equation:


Simplifying
3(7c + 1) + -31 = 15c + 2

Reorder the terms:
3(1 + 7c) + -31 = 15c + 2
(1 * 3 + 7c * 3) + -31 = 15c + 2
(3 + 21c) + -31 = 15c + 2

Reorder the terms:
3 + -31 + 21c = 15c + 2

Combine like terms: 3 + -31 = -28
-28 + 21c = 15c + 2

Reorder the terms:
-28 + 21c = 2 + 15c

Solving
-28 + 21c = 2 + 15c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-15c' to each side of the equation.
-28 + 21c + -15c = 2 + 15c + -15c

Combine like terms: 21c + -15c = 6c
-28 + 6c = 2 + 15c + -15c

Combine like terms: 15c + -15c = 0
-28 + 6c = 2 + 0
-28 + 6c = 2

Add '28' to each side of the equation.
-28 + 28 + 6c = 2 + 28

Combine like terms: -28 + 28 = 0
0 + 6c = 2 + 28
6c = 2 + 28

Combine like terms: 2 + 28 = 30
6c = 30

Divide each side by '6'.
c = 5

Simplifying
c = 5

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