3(7c-5)=-25+6c

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Solution for 3(7c-5)=-25+6c equation: 



3(7c-5)=-25+6c

We move all terms to the left:

3(7c-5)-(-25+6c)=0

We add all the numbers together, and all the variables

3(7c-5)-(6c-25)=0

We multiply parentheses

21c-(6c-25)-15=0

We get rid of parentheses

21c-6c+25-15=0

We add all the numbers together, and all the variables

15c+10=0

We move all terms containing c to the left, all other terms to the right

15c=-10

c=-10/15

c=-2/3

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