3(7c-5)=6c+6c+5-2

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Solution for 3(7c-5)=6c+6c+5-2 equation: 



3(7c-5)=6c+6c+5-2

We move all terms to the left:

3(7c-5)-(6c+6c+5-2)=0

We add all the numbers together, and all the variables

3(7c-5)-(12c+3)=0

We multiply parentheses

21c-(12c+3)-15=0

We get rid of parentheses

21c-12c-3-15=0

We add all the numbers together, and all the variables

9c-18=0

We move all terms containing c to the left, all other terms to the right

9c=18

c=18/9

c=2

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