3(7m+5)=2(m+4)

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Solution for 3(7m+5)=2(m+4) equation: 



3(7m+5)=2(m+4)

We move all terms to the left:

3(7m+5)-(2(m+4))=0

We multiply parentheses

21m-(2(m+4))+15=0



We calculate terms in parentheses: -(2(m+4)), so:

2(m+4)

We multiply parentheses

2m+8

Back to the equation:

-(2m+8)



We get rid of parentheses

21m-2m-8+15=0

We add all the numbers together, and all the variables

19m+7=0

We move all terms containing m to the left, all other terms to the right

19m=-7

m=-7/19

m=-7/19

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