3(7m-4)+4(1-m)=26

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Solution for 3(7m-4)+4(1-m)=26 equation: 



3(7m-4)+4(1-m)=26

We move all terms to the left:

3(7m-4)+4(1-m)-(26)=0

We add all the numbers together, and all the variables

3(7m-4)+4(-1m+1)-26=0

We multiply parentheses

21m-4m-12+4-26=0

We add all the numbers together, and all the variables

17m-34=0

We move all terms containing m to the left, all other terms to the right

17m=34

m=34/17

m=2

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