3(7r-5)=2(r+5)

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Solution for 3(7r-5)=2(r+5) equation: 



3(7r-5)=2(r+5)

We move all terms to the left:

3(7r-5)-(2(r+5))=0

We multiply parentheses

21r-(2(r+5))-15=0



We calculate terms in parentheses: -(2(r+5)), so:

2(r+5)

We multiply parentheses

2r+10

Back to the equation:

-(2r+10)



We get rid of parentheses

21r-2r-10-15=0

We add all the numbers together, and all the variables

19r-25=0

We move all terms containing r to the left, all other terms to the right

19r=25

r=25/19

r=1+6/19

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